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Question

If x+iy=a+ibaib prove that x2+y2=1

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Solution

x+iy=a+ibaib
(x+iy)(xiy)=(a+ib)(aib)×(aib)(a+ib)
x2(iy)2=a2(ib)2a2(ib)2
x2+y2=a2+b2a2+b2=1.

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