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Question

If x+iy=a+ibc+id, prove that (x2+y2)2=a2+b2c2+d2.

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Solution

x+ιy=a+ιbc+ιd..(i)
Taking conjugate both sides xιy=aιbcιd.(ii)
Multiplying (i) and (ii)
(x+ιy)(xιy) = a+ιbc+ιdaιbcιd
x2+y2=a2+b2c2+d2
(x2+y2)2=a2+b2c2+d2

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