Question

If $x=k^2$ and $y=k$ is a solution of the equation $x-5y+6=0$, find $k$.

Answer 1

From question,

$x=k^2$ and $y=k$

Substituting $x$ and $y$ value in the given equation,
$\Rightarrow x-5y+6=0$
$\Rightarrow k^2-5k+6=0$
$\Rightarrow k^2-3k-2k+6=0$
$\Rightarrow k(k-3)-2(k-3)=0$
$\Rightarrow (k-2)(k-3)=0$
$\Rightarrow k=2$ or $k=3$

Hence, $k=2\text{or}3$