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Valency and Oxidation States

If X kJ ene...

Question

If $X k J$ energy must be absorbed to ionise completely all the third shell electrons in a mole of gaseous phosphorus atoms then find out the value of $10^{- 4} X$ will be:
$(I E)_{1} = 1012 (I E)_{2} = 1903 (I E)_{3} = 2912$
$(I E)_{4} = 4957 (I E)_{5} = 6274$ (values are in $k J m o l^{- 1}$ )

1.7058 k J m o l^{- 1}

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2.0346 k J m o l^{- 1}

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17.0329 k J m o l^{- 1}

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3.0248 k J m o l^{- 1}

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Solution

The correct option is C $1.7058 k J m o l^{- 1}$
$(I E)_{T o t a l} = (I E)_{1} + . . . . . . + (I E)_{5}$
$= 1012 + 1903 + 2912 + 4957 + 6274$
$= 1.7058 \times 10^{4} k J m o l^{- 1}$

Option A is correct.

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