Question

If $x^m.y^n=(x+y{)}^{m+n},\text{then}\frac{dy}{dx}=$

• A. y/x
• B. x/y
• C. -y/x
• D. -x/y

Answer 1

The correct option is A

y/x

mlogx + nlogy = (m + n) log (x+y)

$\Rightarrow \frac{dy}{dx}=\frac{y}{x}$