Question

If $x$ mL of a solution of hydrochloric acid containing $73$ g acid per litre would suffice for the exact neutralisation of sodium hydroxide obtained by allowing $0.46$ g of metallic sodium to act upon water, then find the value of $x$.

• A. $10$
• B. $15$
• C. $15.4$
• D. None of the above

Answer 1

The correct option is A $10$

$Na+H_{2}O\to NaOH+\frac{1}{2}{H}_2$
Milliequivalents of $Na=$ Milliequivalents of $NaOH=$ Milliequivalents of $HCl$
$\frac{0.46}{23}\times 1000=\frac{73}{36.5}\times V$ $⟹V=10$ mL

Hence, the value of $x$ is $10$ mL.