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Question

# If x moles of MnO−4 required to oxidise 1 mole of Fe(HC2O4)2 in acidic medium and y moles of Ca(OH)2 are required to react with 1 mole of Fe(HC2O4)2, then determine the value of x and y.

A
x=1, y=1
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B
x=1, y=2
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C
x=2, y=3
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D
None of the above
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Solution

## The correct option is A x=1, y=1Fe(HC2O4)2⇌Fe2++2HC2O−4MnO−4 oxidises Fe2+ to Fe2+ and HC2O−4 to CO2.MnO−4+5Fe2+⟶5Fe3++Mn2+2MnO−4+5C2O−4⟶10CO2+2Mn2+5Fe2+=1MnO2−41Fe2+=15MnO2−45HC2O−4=2MnO−42HC2O−4=45MnO−4Total MnO−4 required by 1 mol of Fe(HC2O4)2 =15+45=1 molFe(HC2O4)2 has two acidic H+.Fe(HC2O4)2⇌Fe2++2HC2O−4⇋2H++2C2O−42H++Ca(OH)2⟶Ca2++2H2OThus, Ca(OH)2 required by 1 mol of Fe(HC2O4)2=1 mol

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