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Question

If x=rsinαcosβ,y=rsinαsinβ and z=rcosα, prove that r2=x2+y2+z2.

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Solution

We have, x2+y2+z2=r2sin2αcos2β+r2sin2αsin2β+r2cos2α

=r2sin2α(cos2β+sin2β)+r2cos2α

=r2sin2α+r2cos2α

=r2

Hence, proved.

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