If x=sin-1(3t-4t3) and y=cos-11-t2, dydx is equal to:
12
23
13
25
Explanation for the correct option
we know that, 3sin-1θ=sin-1(3θ-4θ3)
So, x=3sin-1t
Now,
dxdt=3ddtsin-1t=31-t2
Let t=sinθ, then
y=cos-11-sin2θ=cos-1cosθ=θ=sin-1t⇒dydt=11-t2
dydx=dydt×dtdx=11-t2×1-t23=13
Hence, option C is correct.