If x-sin- y-cos2- find d2y-dx2

x=sinθ , nbsp; dx/d θ=cosθ nbsp;and y=cos2θ , dy/d θ= 2sin 2θ .Now, dy/dx= 2 sin 2θ/cosθ or, dy/dx= 4sinθcosθ/cosθ or, dy/ ...

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Higher Order Derivatives

If x=sinθ, ...

Question

If $x = sin θ$ , $y = cos 2 θ$ , find $\frac{d^{2} y}{d x^{2}}$

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x = a (θ - sin θ)

y = a (1 + cos θ)

\frac{d^{2} y}{d x^{2}}

x = (cos 2 θ - 2 cos θ); y = (sin θ - 2 sin 2 θ)

{(\frac{d^{2} y}{d x^{2}})}_{θ = \frac{π}{2}}

x = 2 sin θ - sin 2 θ

y = 2 cos θ - cos 2 θ

θ \in [0, 2 π],

\frac{d^{2} y}{d x^{2}}

θ = π

x = a (cos θ + log tan \frac{θ}{2})

y = sin θ

\frac{d^{2} y}{d x^{2}}

θ = \frac{π}{4}

x = sin θ, y = cos p θ

m (1 - x^{2}) y_{2} - x y_{1} + p^{2} y = 0

y_{2} = \frac{d^{2} y}{d x^{2}}

y_{1} = \frac{d y}{d x}

m

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