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Question

If xsiny=sin(y+a) and dydx=A1+x22xcosa then the value of A is

A
2
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B
cosa
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C
sina
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D
2
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Solution

The correct option is C sina
xsiny=sin(y+a);dydx=A1+x22xcosa
L.H.S
xsiny=sin(y+a)
xsiny=sinacosy+cosasiny
siny(acosa)=cosysina
sinycosy=sinaxcosa
tany=sinaxcosa;y=tan1(sinaxcosa)
dydx=11+(sinaxcosa)2×[(xcosa)(0)(sina)(10)(xcosa)2]
(xcosa)2(x2+cos2a+sin2a2xcosa)
sin1+x22xcosa
RHS A1+x22xcosa
A=sina, option C is correct

1126104_1140161_ans_a8085044ee054e7a9b93a1d896a09505.jpg

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