Question

If $x=\sqrt{2}$ and $y=\frac{1}{\sqrt{2}}$, find the value of $(x^2-y^2)$.

• A. $\frac{1}{4}$
• B. 0
• C. $\frac{2}{3}$
• D. $\frac{3}{2}$

Answer 1

The correct option is D $\frac{3}{2}$

$x$ $=$ $\sqrt{2}$

$x^2$$=2$

similarly, $y^2$$=$$\frac{1}{2}$

$x^2$$-$$y^2$$=$$\frac{3}{2}$

Hence, Option D is correct.