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Sulphides

If X turns ...

Question

If $(X)$ turns acidified $K_{2} C r_{2} O_{7}$ solution green, then $X$ may be :

S O_{2}

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C O_{2}

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N O_{2}^{-}

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F e^{2 +}

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Solution

The correct options are
B $N O_{2}^{-}$
C $F e^{2 +}$
D $S O_{2}$
$S O_{2}, N O_{2}^{-}$ and $F e^{2 +}$ turns acidified $K_{2} C r_{2} O_{7}$ solution green.

$A : 3 S O_{2} + H_{2} S O_{4} + K_{2} C r_{2} O_{7} \to K_{2} S O_{4} + H_{2} O + C r_{2} (S O_{4})_{3}$ (green)

$C : 3 K N O_{2} + 4 H_{2} S O_{4} + K_{2} C r_{2} O_{7} \to C r_{2} (S O_{4})_{3}$ (green) $+ 4 H_{2} O + K_{2} S O_{4} + 3 K N O_{3}$

$D :$ In the same way, the $F e^{2 +}$ give the $C r_{2} (S O_{4})_{3}$ (green ) on reacting with acidified $K_{2} C r_{2} O_{7}$ solution.

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