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Question

If x+y=12 and xy=27, find the value of x3+y3.

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Solution

Given that, x+y=12 and xy=27

We know,

(x+y)3=x3+y3+3xy(x+y)

Therefore,

123=x3+y3+3×27×12

1728=x3+y3+972

x3+y3=1728972=756

x3+y3=756

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