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Question

If x+y=3 and xy=−18, then find the value of x3+y3.

A
135
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B
199
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C
189
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D
None of these
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Solution

The correct option is A 189
We know that
x3+y3=(x+y)33xy(x+y)
so, x3+y3=(3)33(18)(3)
=27+162
x3+y3=189

1213115_1072380_ans_f5331b93943b46619873d3b6f9398131.jpg

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