If x-y-2- then value of x3-y3-6 x y is -

The correct option is E 8 (x+y)^3=x^3+y^3+3xy (x+y) 2^3=x^3+y^3+3xy(x+y) 8=x^3+y^3+6xy ...

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If x+y=2, the...

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If x+y = 2, then the value of (x $^{3}$ +y $^{3}$ +6xy) is ?

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None of these

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\frac{1}{x} + \frac{1}{y} = 2

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\frac{x}{y} + \frac{y}{x} = - 1, (x, y \neq 0)

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\frac{x}{y} + \frac{y}{x} = - 1 (x, y \neq 0)

x^{3} - y^{3}

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