Question

If $x,y$ and $z$ are the electronegativity, ionisation potential and electron-affinity respectively. Then the electron affinity $\left(z\right)$ in the terms of electronegativity $\left(x\right)$ and ionisation potential $\left(y\right)$ will be:

• A. $z=\frac{x+y}{z}$
• B. $z=\frac{x-y}{z}$
• C. $z=\frac{x^2-y^2}{z}$
• D. $z=2x-y$

Answer 1

The correct option is D $z=2x-y$

$EN=\frac{I.E+E.A}{2}$
EN- Electronegativity
I.E -Ionization energy
E.A- Electron affinity
$E.A=2E.N-I.E$
$E.N=x$
$I.E=y$
$E.A=z$
$\therefore x=\frac{y+z}{2}$
$\Rightarrow z=2x-y$