If x+y+z=0 then x3+y3+z3 =___?
0
-3xyz
3xyz
2xyz
x3+y3+z3–3xyz = (x+y+z)(x2+y2+z2−2xy–2yz–2zx)
If x+y+z=0 then x3+y3+z3–3xyz=0, ⟹x3+y3+z3=3xyz