Question

If $x,y,z$ are three consecutive positive integer, then $\log (1+zx)$ is equal to

Answer 1

$y=x+1$

$z=y+1=x+2$

$\therefore$ $log(1+xz)=log(1+x(x+2\left)\right)$

$=log(1+x^2+2x)$

$=log\left[{(x+1)}^2\right]=log{y}^2$

$=2logy$