wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

If x, y, z are three + ive real numbers, then minimum value of y+zx+z+xy+x+yz is

A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 6
L. H. S =(yz+xy)+(zx+xz)+(yz+zy)
Each pair is 2 as A.M. G.M.
L.H.S 6. Hence the minimum value is 6
Another form:
yz(y+z2x)+zx(z+x2y)+xy(x+y2z)0
or yz(y+z)+zx(z+x)+xy(x+y)6xyz
or yx+zx+zy+xy+xz+yz>6 etc.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Inequalities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon