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Question

If y=1cosθ,x=1sinθ, then dydx at θ=π4 is

A
1
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Solution

The correct option is A 1
Given, y=1cosθ
dydθ=sinθ
Also given, x=1sinθ
dxdθ=cosθ
Therefore, dydx=sinθcosθ=tanθ at θ=π4 will be
[dydx]θ=π4=tanπ4=1

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