If y-1-x1-x21-x4- then d y-d x at x-0 isA- 1B- -1C- 2D- 0

The correct option is A 1Multiplying numerator amp; denominator by (1 x) y = (1 x)(1+x)(1+x^2)(1+x^4)/1 x ⇒ y = 1 x^8/1 x (dy/dx )_x 0=1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Definition of Functions

If y=1+x1+x21...

Question

$I f y = (1 + x) (1 + x^{2}) (1 + x^{4}), t h e n \frac{d y}{d x} a t x = 0 i s$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

y = (1 + x) (1 + x^{2}) (1 + x^{4}) . . . . . . . . . (1 + x^{2 n})

(\frac{d y}{d x})

x = 0

If $y = (1 + x) (1 + x^{2}) (1 + x^{4}), t h e n \frac{d y}{d x} a t x = 1$

y = (1 + x) (1 + x^{2}) (1 + x^{4}) \dots \dots (1 + x^{2^{n}})

\frac{d y}{d x}

y = (1 + x) (1 + x^{2}) (1 + x^{4}) \dots (1 + x^{2^{n}})

\frac{d y}{d x}

y = (1 + x) (1 + x^{2}) (1 + x^{4}) . . . (1 + x^{2^{n}})

\frac{d y}{d x}

x = 0

Join BYJU'S Learning Program