CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If y2=ax2+bx+c, then y3.d2ydx2 is
  1. A function of y only
  2. A function of x and y
  3. A function of x only
  4. A constant


Solution

The correct option is D A constant
y2=ax2+bx+c .......... (1)

Differentiate w.r.t x

2yy1=2ax+b .......... (2)
Here, y1=dydx

Again, diff w.r.t to x

2y21+2yy2=2a

y21+yy2=a ............. (3)

y2y21+y3y2=a(ax2+bx+c)   using (2)

(ax+b2)2+y3y2=a2x2+abx+ac

a2x2+abx+b24+y3y2=a2x2+abx+ac

y3y2=acb24

y3y2=4acb24 is a constant.

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More...



footer-image