Question

If $y^2=(x-c{)}^3$, then find $\frac{dy}{dx}$.

Answer 1

We have,

$y^2=(x-c{)}^3$

On differentiating w.r.t $x$, we get

$2y\frac{dy}{dx}=3(x-c{)}^2$

$\frac{dy}{dx}=\frac{3(x-c{)}^2}{2y}$

Hence, this is the answer.