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B
y2
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C
y3
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D
y4
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Solution
The correct option is A2y Given, y=Ax+Bx2 On differentiating w,r,t x, we get ⇒dydx=−Ax2+2Bx Again differentiating, we get ⇒d2ydx2=2Ax3+2B ∴x2d2ydx2=2Ax+2Bx2=2y