If y - 14 x- A2Hence prove- y12 - y-

y= 1 4 (x± A) ^ 2 y _ 1 = dy dx = 1 4 × 2(x± A) y _ 1 ^ 2 = 1 4 (x± A) ^ 2 =y Hence proved. ...

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Algebra of Derivatives

If y = 14 x...

Question

If $y = \frac{1}{4} (x \pm A)^{2}$
Hence prove: $y_{1}^{2} = y$ .

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4 x + \frac{6}{y} = 15

6 x - \frac{8}{y} = 14

a

y = a x - 2

A = [\begin{matrix} 4 & 3 \\ 2 & 5 \end{matrix}]

A^{2} = x A + y I = O

4 x + \frac{6}{y} = 15

6 x - \frac{8}{y} = 14

y = p x - 2

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