Question

If $y=\frac{(\sin x+x^2)}{\cot 2x}$, find $\frac{dy}{dx}$ ?

Answer 1

$y=(x^2+\sin x)\left(\tan 2x\right)dx$

$\frac{dy}{dx}=(x^2+\sin x)\left(2{\sec }^{2}2x\right)+\left(\tan 2x\right)(2x+\cos x)$

$\frac{dy}{dx}=2{\sec }^{2}2x.x^2+2{\sec }^{2}2x.\sin x+\tan 2x.2x+\tan 2x.\cos x.$