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Question

If y=(sinx+x2)cot2x, find dydx ?

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Solution

y=(x2+sinx)(tan2x)dx
dydx=(x2+sinx)(2sec22x)+(tan2x)(2x+cosx)
dydx=2sec22x.x2+2sec22x.sinx+tan2x.2x+tan2x.cosx.

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