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Question

If y=ex2, then what is dydx at x=π equal to?

A
(1+π)eπ2
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B
2πeπ2
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C
2eπ2
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D
eπ2
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Solution

The correct option is A 2πeπ2
We have y=ex2

Differentiate with respect to x, we get

dydx=ex22x

At x=π we get

dydx(x=π)=eπ22π=2πeπ2

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