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Question

If y=exsinx, then find dydx

A
ex(sinx+cosx)
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B
ex(sinxcosx)
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C
exsinx
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D
None of these
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Solution

The correct option is A ex(sinx+cosx)
Given that
y=ex.sinx
On differentiating, we get
dydx=sinxddxex+exddxsinx
dydx=sinxex+excosx
dydx=ex(sinx+cosx)

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