wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If y=exsinx, then find dydx

A
ex(sinx+cosx)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
ex(sinxcosx)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
exsinx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A ex(sinx+cosx)
Given that
y=ex.sinx
On differentiating, we get
dydx=sinxddxex+exddxsinx
dydx=sinxex+excosx
dydx=ex(sinx+cosx)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebra of Derivatives
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon