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Algebra of Derivatives

If y=ex+x2+...

Question

If $y = e^{x} + x^{2} + log x$ , then find $\frac{d y}{d x}$ .

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Solution

$y = e^{x} + x^{2} + log x$

$\frac{d y}{d x} = e^{x} + 2 x + \frac{1}{x}$

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Similar questions

x^{y} = e^{x - y}

then prove that

\frac{d y}{d x} = \frac{log x}{(log x + 1)^{2}}

\frac{d y}{d x}

y = e^{x} + u^{x} - log x

x^{y} = e^{x - y}

\frac{d y}{d x} = \frac{l o g x}{(1 - l o g x)^{2}}

.

x^{y} = e^{x - y}

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, then prove that

\frac{d y}{d x} = \frac{log x}{{[log e x]}^{2}}

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