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Question

If y=f(x2+2) and f(3)=5, then dydx at x=1 is _____

A
5
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B
25
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C
15
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D
10
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Solution

The correct option is C 10
y=f(x2+2)
Using chain rule of differentiation
dydx=dd(x2+2)[f(x2+2)]ddx(x2+2)
=f(x2+2)2x=2xf(x2+2)

Hence dydxx=1=21f(12+2)=2f(3)=25=10

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