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Question

If y=[x+x21]15+[xx21]15, then (x21)d2ydx2+xdydx is equal to.

A
125y
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B
225y2
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C
225y
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D
224y2
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Solution

The correct option is B 225y
dydx=15(x+x21)14(1+2x2x21)+15(xx21)14(12x2x21)
=15(x+x21)14 (x21+x2x21)+15(x(x21)14(x21x)
dydx=15(x+x21)15x2115(xx21)15x21
x21dydx=15(x+x21)1515(xx21)15
2x2x21 dydx +d2ydx2 x21= 225(x+x21)15+225(xx21)15x21
xdydx+(x21)d2ydx2=225y.

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