Question

If $y={(\sin B+\cos B)}^2$, then find $\frac{dy}{dx}$.

Answer 1

$y=(sinB+cosB{)}^2$

$\frac{dy}{dx}=\frac{d}{dx}(sinB+cosB{)}^2$

ad there are no terms of $x$, so the differentiation will be $0$

$\frac{dy}{dx}=0$