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Higher Order Derivatives

If y= sin B...

Question

If $y = {(sin B + cos B)}^{2}$ , then find $\frac{d y}{d x}$ .

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Solution

$y = (s i n B + c o s B)^{2}$

$\frac{d y}{d x} = \frac{d}{d x} (s i n B + c o s B)^{2}$

ad there are no terms of $x$ , so the differentiation will be $0$

$\frac{d y}{d x} = 0$

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