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Question

If y=[log(log(logx))]2, then Find dydx

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Solution

y=[log(log(logx))]2,
dydx=2log(log(logx))ddxlog(log(logx)).
2log(log(logx)).1log(logx)ddxlog(logx).
2 log(log(logx))1log(logx).1logx.1x

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