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Question

If Y=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯AB+¯¯¯¯BC+A¯¯¯¯C+CD, then dual of Y is

A
(A+¯¯¯¯B)(B+¯¯¯¯C)(C+D)
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B
(A¯¯¯¯B+B¯¯¯¯C+¯¯¯¯AC)(C+D)
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C
(A+¯¯¯¯B)(¯¯¯¯B+C)(A+¯¯¯¯C)(C+D)
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D
(A¯¯¯¯B+¯¯¯¯BC+¯¯¯¯AC)(CD)
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Solution

The correct option is B (A¯¯¯¯B+B¯¯¯¯C+¯¯¯¯AC)(C+D)
Y=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯AB+¯¯¯¯BC+A¯¯¯¯C+CD

=(¯¯¯¯¯¯¯¯¯¯¯¯AB)(¯¯¯¯¯¯¯¯¯¯¯¯BC)(¯¯¯¯¯¯¯¯¯A¯¯¯¯C)+CD

Y=(A+¯¯¯¯B)(B+¯¯¯¯C)(¯¯¯¯A+C)+CD

Dual of Y=(A¯¯¯¯B+B¯¯¯¯C+¯¯¯¯AC)(C+D)

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