Question

If $y=sec{x}^0$ then $\frac{dy}{dx}=$

• A. $secxtanx$
• B. $sec{x}^{0}tan{x}^0$
• C. $\frac{\pi }{180}sec{x}^{0}tan{x}^0$
• D. $\frac{180}{\pi }sec{x}^{0}tan{x}^0$

Answer 1

The correct option is C $\frac{\pi }{180}sec{x}^{0}tan{x}^0$

Give $y=sec{x}^0$
$=sec\frac{x\pi }{{180}^o}(\because x^o=\frac{x\pi }{{180}^o}radians)$
$\therefore \frac{dy}{dx}=\frac{\pi }{{180}^o}sec{x}^{o}tan{x}^o$