CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

First Principle of Differentiation

If y=sin-1x...

Question

If $y = {sin}^{- 1} (x^{2})$ then find $\frac{d y}{d x}$ using first principle.

A

\frac{2 x}{\sqrt{1 - x^{4}}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

\frac{2}{\sqrt{1 - x^{2}}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

\frac{x}{\sqrt{1 - x^{4}}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

- \frac{1}{\sqrt{1 - x^{4}}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{2 x}{\sqrt{1 - x^{4}}}$
$y = {sin}^{- 1} (x^{2})$

$\frac{d y}{d x} = \frac{1}{\sqrt{1 - x^{4}}} \times 2 x$

$= \frac{2 x}{\sqrt{1 - x^{4}}}$

Suggest Corrections

thumbs-up

0

Similar questions

y = {sin}^{- 1} (x^{2} \sqrt{1 - x} - \sqrt{x} \sqrt{1 - x^{4}}),

\frac{d y}{d x} .

\int x \sqrt{\frac{1 - x^{2}}{1 + x^{2}}} d x =

y = \frac{x^{4} + x^{2} + 2}{x^{2} - x + 1}

\frac{d y}{d x} = . . . . . . . . . . . . . . . . . . .

y = 1 + \frac{x}{1!} + \frac{x^{2}}{2!} + \frac{x^{3}}{3!} + \frac{x^{4}}{4!} + . . . . \infty

, then find the value of

\frac{d y}{d x}

y = log (\frac{1 - x^{2}}{1 + x^{2}}),

\frac{d y}{d x}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Derivative from First Principles

MATHEMATICS

Watch in App

explore_more_icon

Explore more

First Principle of Differentiation

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon