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Question

If y=sin x+y, then dydx=

(a) sin x2 y-1

(b) sin x1-2 y

(c) cos x1-2 y

(d) cos x2 y-1

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Solution

(d) cos x2 y-1

We have, y=sinx+ySquaring both sides, we get,y2=sinx+yy2-y=sinx2ydydx-dydx=cosxdydx2y-1=cosxdydx=cosx2y-1

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