If y - -x2 -2x -1 - -x2 - 2x - 1- then y is-

The correct option is E | x 1| |x + 1| y=√( x ^ 2 2x+1 ) +√( x ^ 2 +2x+1 ) =√( (x 1) ^ 2 ) +√( (x+1) ^ 2 ) ∴ y=|x 1|+|x+1| ...

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Real Valued Functions

If y = √x2 ...

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If y = $\sqrt{x^{2} - 2 x + 1} + \sqrt{x^{2} + 2 x + 1}$ , then y is:

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2(x + 1)

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| x - 1 | | x + 1 |

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none of these

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If $y = [\frac{x^{2} + 1}{x + 1}], t h e n \frac{d y}{d x}$ =?

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y = 2 {tan}^{- 1} x + {sin}^{- 1} \frac{2 x}{1 + x^{2}}

y = 2 x + {cot}^{- 1} x + log (\sqrt{1 + x^{2}} - x),

y = \frac{x^{2}}{2} + \frac{1}{2} x \sqrt{x^{2} + 1} + ln \sqrt{x + \sqrt{x^{2} + 1}}

x y^{'} + log y^{'}

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