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Question

If y=x+y+x+y+....,then dydx is equal to

A
12y1
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B
y2x2y32xy1
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C
(2y1)
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D
None of these
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Solution

The correct option is B y2x2y32xy1
y=x+y+y
(y2x)=2y
or (y2x)2=2y
Differentiating both sides w.r.t. x, then
2(y2x)(2ydydx1)=2dydx
dydx=(y2x)2y32xy1

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