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B
dydx=y2y−x
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C
dydx=2y2x−y
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D
None of these
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Solution
The correct option is Bdydx=y2y−x We have y=x+1x+1x+1x+⋯ =x+1y or y2=xy+1 or 2ydydx=y+xdydx+0[Differentiating both sides w.r.t. x] or dydx(2y−x)=y or dydx=y2y−x