If you subtract a number x from 17 times of that number, and then take the
cube of the difference, what will be the result?

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Solution

Dear Student,
$A c c o r d i n g t o t h e q u e s t i o n, t h e f i r s t n u m b e r i s x a n d t h e s e c o n d n u m b e r i s 17 x . D i f f e r e n c e o f t h e n u m b e r s = (17 x - x) C u b e o f t h e d i f f e r e n c e = (17 x - x)^{3} = (16 x)^{3} = 4096 x^{3}$
Regards

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If you subtract a number x from 17 times of that number, and then take the cube of the difference, what will be the result?

Dear Student, According to the question, the first number is x and the second number is 17 x . Difference of the numbers = (17x-x)Cube of the difference =(17x-x)3 =(16x)3 = 4096x3 Regards

If you subtract a number x from 17 times of that number, and then take the
cube of the difference, what will be the result?

Dear Student,
$A c c o r d i n g t o t h e q u e s t i o n, t h e f i r s t n u m b e r i s x a n d t h e s e c o n d n u m b e r i s 17 x . D i f f e r e n c e o f t h e n u m b e r s = (17 x - x) C u b e o f t h e d i f f e r e n c e = (17 x - x)^{3} = (16 x)^{3} = 4096 x^{3}$
Regards