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Question

If z1=(2i) and z2=(1+i), then z1+z2+1z1z2+i is equal to

A
22
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B
42
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C
2
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D
82
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Solution

The correct option is A 22
z1+z2+1z1z2+i=(2i)+(1+i)+1(2i)(1+i)+i=4(1i)

Now,
z1+z2+1z1z2+i=|4||1i|=22

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