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Question

If z=−1+3i then z2+2z+10=

A
0
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B
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C
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Solution

The correct option is A 0
z2+2z+10
=(z+1)2+101
=(z+1)2+9
=(1+3i+1)2+9
=(3i)2+9
=9+9
=0
Hence, z2+2z+10=0 where z=1+3i.

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