If $z_{1} = 6 + i$ $z_{2} = 3 - 4 i$ then find $z_{1} z_{2}$

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Solution

$z_{1} = 6 + i z_{2} = 3 - 4 i z_{1} z_{2} = (6 + i) (3 - 4 i) z_{1} z_{2} = 18 + 3 i - 24 i + 4 = 22 - 21 i$

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