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Question
If z1=√3−i,z2=1+i√3, then amp(z1+z2)=
If z1=√3−i,z2=1+i√3, then amp(z1+z2)=
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Solution
The correct option is A π12
z1=√3−i,z2=1+i√3 $ z_1+z_2=(\sqrt { 3 }+1)+i(\sqrt{3}-1) $z1+z2=(√3+1)+i(√3−1)|z1+z2|=√(√3+1)2+(√3−1)2=2√2
z1=√3−i,z2=1+i√3
$ z_1+z_2=(\sqrt { 3 }+1)+i(\sqrt{3}-1) $
z1+z2=(√3+1)+i(√3−1)
|z1+z2|=√(√3+1)2+(√3−1)2=2√2
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