wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If |z2|=min{|z1|,|z5|}, where z is a complex number, then possible value(s) of Re(z) is/are

A
32
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
52
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
72
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
92
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A 32
C 72
Given : |z2|=min{|z1|,|z5|}
Let z=x+iy
When |z1|<|z5|
(x1)2+y2<(x5)2+y22x+1<10x+25x<3
Now,
|z2|=|z1|
z is perpendicular bisector of line segment joining points (2,0) and (1,0)
x=32

When |z1||z5|
x3
Now,
|z2|=|z5|
z is perpendicular bisector of line segment joining the points (2,0) and (5,0)
x=72

Hence, the possible values of Re(z) are 32 and 72.

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon