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Question
If |z+2i|≤2, then the least value of |z−√3+i| is :
If |z+2i|≤2, then the least value of |z−√3+i| is :
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Solution
The correct option is B 0
|z−√3+i|=|(z+2i)−(√3+i)|
⇒|z−√3+i|≥||z+2|−|√3+i|| [|z1−z2|≥||z1|−|z2||]≥2−√3+1=2−2=0
Hence least value of |z−√3+i| is 0
|z−√3+i|=|(z+2i)−(√3+i)|
⇒|z−√3+i|≥||z+2|−|√3+i|| [|z1−z2|≥||z1|−|z2||]
≥2−√3+1=2−2=0
Hence least value of |z−√3+i| is 0
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