CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If z be a complex number satisfying z4+z3+2z2+z+1=0 then |z| equals to

A
|ω|
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
34
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
|±i|
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A |ω|
C |±i|
(z4+z3+z2)+(z2+z+1)=0
z2(z2+z+1)+1(z2+z+1)=0
(z2+1)(z2+z+1)=0
Hence
z2+1=0
z=±i
and
z2+z+1=0
z=w,w2
Hence
|z|
=|i|
=|w|
=|w2|
=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Parametric Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon